#include<stdio.h>
#include<math.h>
int main()
{
    int i;
    for(i=0; ;i++)
    if(((i*8+7)*8+1)*8+1 == (34*i+15)*17+4)
    {
        printf("the requride number is: %d\n",(34*i+15)*17+4);
        break;
    }
}


